#include <iostream>
#include <cmath>
using namespace std;
int days[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

int main()
{
	int cnt = 0;
	for(int i = 1; i <= 12; i ++ )
	{
		int a = i/10, b = i%10;
		for(int j = 1; j <= days[i]; j ++ )
		{
			int c = j/10, d = j%10;
			if((a + 1 == b && b + 1 == c) || (b + 1 == c && c + 1 == d))
				cnt++;
		}
	}
	cout<<cnt<<endl;
}

容易看出顺子和2022没有关系 直接枚举月日即可