模拟即可

题目参考出处 霓虹【算法赛】 - 蓝桥云课 (lanqiao.cn)

双倍经验了算是，将原题的输入读入改为循环枚举当前数和下一个数，将这两数的字符串形式作为题目的输入处理即可

#include <bits/stdc++.h>

using namespace std;

using i64 [[maybe_unused]] = long long;
template<typename T, class comparer = greater<T>>
using heap = priority_queue<T, vector<T>, comparer>;
const char &ln = '\n';
#define parse static_cast

signed main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    int arr[10][10]{
            {0, 4, 3, 3, 4, 3, 2, 3, 1, 2},
            {4, 0, 5, 3, 2, 5, 6, 1, 5, 4},
            {3, 5, 0, 2, 5, 4, 3, 4, 2, 3},
            {3, 3, 2, 0, 3, 2, 3, 2, 2, 1},
            {4, 2, 5, 3, 0, 3, 4, 3, 3, 2},
            {3, 5, 4, 2, 3, 0, 1, 4, 2, 1},
            {2, 6, 3, 3, 4, 1, 0, 5, 1, 2},
            {3, 1, 4, 2, 3, 4, 5, 0, 4, 3},
            {1, 5, 2, 2, 3, 2, 1, 4, 0, 1},
            {2, 4, 3, 1, 2, 1, 2, 3, 1, 0}
    };
    string a, b;
    int ans = 0;
    for(int i = 1000; i < 2024; ++i) {
      a = to_string(i), b = to_string(i + 1);
    for(int i = 0; i < a.length(); ++i) {
        int x = a[i] ^ '0', y = b[i] ^ '0';
        ans += arr[x][y];
    }
    }
    cout << ans;
    return 0;
}

# '10':4  表示1到0的转变要4次
d={'10':4,'21':5,'32':2,'43':3,'54':3,'65':1,'76':5,'87':4,'98':1,'09':2}
c=0
for i in range(1001,1011):
    i1=str(i-1)
    i=str(i)
    for _ in range(4):
        if i[_]!=i1[_]:
            c+=d[i[_]+i1[_]]
print(c)